2x^2+19=-10x

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Solution for 2x^2+19=-10x equation: 



2x^2+19=-10x

We move all terms to the left:

2x^2+19-(-10x)=0

We get rid of parentheses

2x^2+10x+19=0

a = 2; b = 10; c = +19;
Δ = b2-4ac
Δ = 102-4·2·19
Δ = -52
Delta is less than zero, so there is no solution for the equation

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